Quantitative Aptitude Ques 2126

Question: Directions: In the following questions two equations numbered I and II are given. You have to solve both the equations and give answer. [RBI (Assistant) Scale 2011]

I. $ x^{2}+5x+6=0 $
II. $ y^{2}+3y+2=0 $

Options:

A) If $ x>y $

B) If $ x\ge y $

C) If $ x<y $

D) If $ x\le y $

E) If $ x=y $ or the relationship cannot be established

Show Answer

Answer:

Correct Answer: D

Solution:

  • I. $ x^{2}+5x+6=0 $

$ \Rightarrow $ $ x^{2}+2x+3x+6=0 $
$ \Rightarrow $ $ x(x+2)+3(x+2)=0 $

$ \Rightarrow $ $ (x+3)(x+2)=0 $
$ \Rightarrow $ $ x=-3, $ $ -2 $ II. $ y^{2}+3y+2=0 $

$ \Rightarrow $ $ y^{2}+2y+y+2=0 $
$ \Rightarrow $ $ y(y+2)+1(y+2)=0 $

$ \Rightarrow $ $ (y+1)(y+2)=0 $
$ \Rightarrow $ $ y=-1, $ $ -2 $ Hence, $ x\le y. $