Quantitative Aptitude Ques 2120

Question: A person travels a certain distance at 3 km/h and reaches 15 min late. If he travels at 4 km/h, he reaches 15 min earlier. The distance he has to travel is

Options:

A) 4.5 km

B) 6 km

C) 7.2 km

D) 12 km

Show Answer

Answer:

Correct Answer: B

Solution:

  • Let the certain distance bed and timer. Now, by given condition, $ \frac{d}{3}=(t+15)\min =\frac{(t+15)}{60}h $

$ \Rightarrow $ $ 20d=t+15 $
$ \Rightarrow $ $ t=20d-15 $ … (i) and $ \frac{d}{4}=(t-15)\min =\frac{(t-15)}{60}h $

$ \Rightarrow $ $ 15d=t-15 $
$ \Rightarrow $ $ t=15d+15 $ … (ii) From Eqs. (i) and (ii), we get $ 20d-15=15d+15 $
$ \Rightarrow $ $ 5d=30 $

$ \therefore $ $ d=6km $

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