Question: A can do a certain work is 12 days. B is 60% more efficient than A. How many days will B and A together take to do same job?
Options:
A) $ \frac{80}{13} $
B) $ \frac{70}{13} $
C) $ \frac{75}{13} $
D) $ \frac{60}{13} $
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Answer:
Correct Answer: D
Solution:
- In such questions, we have to calculate the number of days of each worker.
In this question,
The efficiency of B is 60% more than, A and time taken by A is 12 days.
Now, we find the number of days of B’s work,
By the formula,
Time $ =\frac{100}{100+x}\times $ Total days taken by A
where, $ x= $ efficiency percentage
$ \therefore $ Time taken by $ B=\frac{100}{160}\times 12=\frac{15}{2}days $
$ \therefore $ (A + B)’s 1 day work $ =\frac{1}{2}+\frac{2}{15}=\frac{5+8}{60}=\frac{13}{60} $
Hence, the work will be completed in $ \frac{60}{13} $ days.