SATHEE: Quantitative Aptitude Ques 2090

Quantitative Aptitude Ques 2090

Question: Directions: In the following questions, two equations numbered I and II are given. You have to solve both the equations and give answer. [IBPS (RRB) Grade A 2012]

I. $ {{(169)}^{1/2}}x+\sqrt{289}=134 $ II. $ {{(361)}^{1/2}}y^{2}-270=1269 $

Options:

A) If $ x>y $

B) If $ x\ge y $

C) If $ x<y $

D) If $ x\le y $

E) If $ x=y $ or the relationship cannot be established

Show Answer

Answer:

Correct Answer: B

Solution:

$ {{(169)}^{1/2}}x+\sqrt{289}=134 $ (i) $ {{(361)}^{1/2}}y^{2}-270=1269 $ (ii) Above equations can be rewritten as, I. $ 13x+17=134 $

$ \Rightarrow $ $ 13x=134-17 $

$ \Rightarrow $ $ 13x=117 $
$ \Rightarrow $ $ x=\frac{117}{13}=9 $

$ \therefore $ $ x=9 $ II. $ 19y^{2}-270=1269 $

$ \Rightarrow $ $ 19y^{2}=1269+270 $

$ \Rightarrow $ $ 19y^{2}=1539 $

$ \Rightarrow $ $ y^{2}=\frac{1539}{19} $
$ \Rightarrow $ $ y^{2}=81 $

$ \therefore $ $ y=\pm 9 $ Hence, $ x\ge y $

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