Quantitative Aptitude Ques 2074
Question: The product of two numbers is 2028 and their HCF is 13. The number of such pairs is
Options:
A) 1
B) 2
C) 3
D) 4
Show Answer
Answer:
Correct Answer: B
Solution:
- Let the numbers be 13a and 13b. where a and b are coprime
$ \therefore $ LCM of 13a and 13b = 13ab product of numbers $ =HCF\times LCM $
$ \Rightarrow 2028=13\times 13ab $
$ \Rightarrow ab=\frac{2028}{13\times 13}=12 $ Pairs satisfying the condition = (1,12) and (3,4)
$ \therefore $ Number of pairs is 2
BETA
