Quantitative Aptitude Ques 2074

Question: The product of two numbers is 2028 and their HCF is 13. The number of such pairs is

Options:

A) 1

B) 2

C) 3

D) 4

Show Answer

Answer:

Correct Answer: B

Solution:

  • Let the numbers be 13a and 13b. where a and b are coprime

$ \therefore $ LCM of 13a and 13b = 13ab product of numbers $ =HCF\times LCM $

$ \Rightarrow 2028=13\times 13ab $

$ \Rightarrow ab=\frac{2028}{13\times 13}=12 $ Pairs satisfying the condition = (1,12) and (3,4)

$ \therefore $ Number of pairs is 2

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