Quantitative Aptitude Ques 2058

Question: Two pipes X and Y can fill a cistern in 6 and 7 min, respectively. Starting with pipe X, both the pipes are opened alternately, each for 1 min. In what time will they fill the cistern?

Options:

A) $ 6\frac{2}{7}\min $

B) $ 6\frac{3}{7}\min $

C) $ 6\frac{5}{7}\min $

D) $ 6\frac{1}{7}\min $

Show Answer

Answer:

Correct Answer: B

Solution:

  • Part filled by X In 1st min and Y in the 2nd min $ =( \frac{1}{6}+\frac{1}{7} )=\frac{13}{42} $ Part filled by (X + Y) working alternatively is 6min $ =\frac{1}{2}\times \frac{13}{42}\times 6=\frac{13}{14} $

$ \therefore $ Remaining part $ =( 1-\frac{13}{14} )=\frac{1}{14} $ Now, it is the turn of X, one-sixth part is filled in 1 min. One-fourteenth part is filled in $ ( 6\times \frac{1}{14} )\min =\frac{3}{7}\min $

$ \therefore $ Required time $ =( 6+\frac{3}{7} )=6\frac{3}{7}\min $