A) $ 96\sqrt{3}cm^{2} $
B) $ 48\sqrt{3}cm^{2} $
C) $ 48cm^{2} $
D) $ 64\sqrt{3}cm^{2} $
Correct Answer: B
$ \Rightarrow $ $ 60{}^\circ +x+x=180{}^\circ $
$ \Rightarrow $ $ 2x=120{}^\circ $
$ \Rightarrow $ $ x=60{}^\circ $
$ \therefore $ $ \Delta BCG $ Is an equilateral triangle as all the angles are $ 60{}^\circ . $ Area of $ \Delta BCG=\frac{\sqrt{3}}{4}\times 8^{2}=\frac{\sqrt{3}}{4}\times 8\times 8=16\sqrt{3}cm^{2} $
$ \therefore $ Area of $ \Delta ABC=3\times \Delta BCG=3\times 16\sqrt{3}=48\sqrt{3}cm^{2} $