SATHEE: Quantitative Aptitude Ques 2028

Quantitative Aptitude Ques 2028

Question: Directions: In the following questions, two equations numbered I and II are given. You have to solve both the equations and give answer [IBPS RRB (Office Assistant) 2012]

I. $ 4x+3y={{(1600)}^{1/2}} $ II. $ 6x-5y={{(484)}^{1/2}} $

Options:

A) If $ x>y $

B) If $ x\ge y $

C) If $ x<y $

D) If $ x\le y $

E) If $ x=y $ or relationship cannot be established

Show Answer

Answer:

Correct Answer: A

Solution:

I. $ 4x+3y={{(1600)}^{1/2}} $

$ \Rightarrow $ $ 4x+3y=40 $ … (i) II. $ 6x-5y={{(484)}^{1/2}} $ $ 6x-5y=22 $ … (ii) On multiplying Eq. (i) by 6 and Eq, (ii) by 4, we get $ y=\frac{152}{38}=4 $ On putting the value of y in Eq. (ii), we get $ 6x-5(4)=22 $

$ \Rightarrow $ $ 6x=22+20 $
$ \Rightarrow $ $ 6x=42 $

$ \therefore $ $ x=7 $ Hence, $ x>y $

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Quantitative Aptitude Ques 2028

Question: Directions: In the following questions, two equations numbered I and II are given. You have to solve both the equations and give answer [IBPS RRB (Office Assistant) 2012]

Options:

Answer:

Solution:

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