Quantitative Aptitude Ques 2005

Question: A shopkeeper bought a table marked at Rs. 200 at successive discounts of 10% and 15%, respectively. He spent Rs. 7 on transport and sold the table for Rs. 208. Find his profit per cent.

Options:

A) 32%

B) 30%

C) 40%

D) 35%

Show Answer

Answer:

Correct Answer: B

Solution:

  • Marked price of table = Rs. 200 Two successive discounts of 10% and 15%.

$ \therefore $ Overall discount percentage $ =( r _1+r _2+\frac{r _1r _2}{100} )% $ $ r _1=-10 $ and $ r _2=-15 $ [ $ - $ ve because discounts are given] $ =( 10-15+\frac{150}{100} )%=(-25+1.5)%=-23.5% $ Overall discount on table = 23.5% of 200 $ =\frac{23.5}{100}\times 200=Rs\text{. 47} $ Now, cost price of table $ =200-47=153 $ Now, he spends Rs. 7 on transportation.

$ \therefore $ Total cost price of table $ =153+7=Rs\text{. 160} $ Now, given selling price of table = Rs. 208 Gain percentage $ =( \frac{SP-CP}{CP} )\times 100% $ $ =\frac{208-160}{160}\times 100%=\frac{48}{160}\times 100%=30% $

$ \therefore $ Profit percentage of shopkeeper $ =30% $