Quantitative Aptitude Ques 2002

Question: What was the day of the week on 17th July, 1776?

Options:

A) Wednesday

B) Thursday

C) Monday

D) Saturday

Show Answer

Answer:

Correct Answer: A

Solution:

  • Period upto 17th July, 1776 = (1775 yr + Period from 1st January 1776 to 17th July, 1776) Counting of odd days In 1600 yr = 0
    $ \Rightarrow $ In 100 yr = 5 75 yr = 18 leap years + 57 ordinary years $ =(18\times 2+57\times 1) $ odd days = 93 odd days = (13 weeks + 2 days) = 2 odd days

$ \therefore $ 1775 yr have $ (0+5+2) $ odd days = 7 odd days = 1 week + 0 odd day = 0 odd day Number of days between 1.1.1776 to 17.7.1776 January + February + March + April + May + June + July $ 31+29+31+30+31+30+17 $ = 199 days = 28 weeks + 3 odd days

$ \therefore $ Total number of odd days $ =(3+0)=3 $ Hence, the required day is Wednesday.