Question: A $ \Delta DEF $ is formed by joining the mid-points of the sides of $ \Delta ABC. $ Similarly, a $ \Delta PQR $ is formed by joining the mid-points of the sides of the $ \Delta DEF. $ If the sides of the $ \Delta PQR $ are of lengths 1, 2 and 3 units, then what is the perimeter of the $ \Delta ABC $ ?
Options:
A) 18 units
B) 24 units]
C) 48 units
D) 50 units
Show Answer
Answer:
Correct Answer: B
Solution:
Perimeter of $ \Delta PQR=1+2+3=6units $
Now, in $ \Delta DEF $
$ \frac{DQ}{DF}=\frac{1}{2}=\frac{PQ}{FE} $
So, $ 2PQ=FE $
Similarly, $ DF=2PR $
and $ DE=2QR $
$ \therefore $ Perimeter of
$ \Delta DEF=2\times 6=12units $
Similarly, Perimeter of $ \Delta ABC=2\times $ Perimeter of $ \Delta DEF $
$ =2\times 12=24units $
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