A) $ 45{}^\circ $
B) $ 60{}^\circ $
C) $ 75{}^\circ $
D) $ 95{}^\circ $
Correct Answer: C
$ \Rightarrow $ $ \angle DCB=180{}^\circ -120{}^\circ =60{}^\circ $ Since, angles of a quadrilateral is equal to $ 360{}^\circ . $
$ \therefore $ $ \angle ADC=360{}^\circ -[120{}^\circ +105{}^\circ +60{}^\circ ] $ $ =360{}^\circ -285{}^\circ =75{}^\circ $