SATHEE: Quantitative Aptitude Ques 1978

Quantitative Aptitude Ques 1978

Question: In the given figure, O is the centre of a circle and $ \angle OAB=50{}^\circ . $ Then, $ \angle BOD $ is equal to

Options:

A) $ 130{}^\circ $

B) $ 50{}^\circ $

C) $ 100{}^\circ $

D) $ 80{}^\circ $

Show Answer

Answer:

Correct Answer: C

Solution:

$ OA=OB $
$ \Rightarrow $ $ \angle OBA=\angle OAB=50{}^\circ $ [angle substend by same segments, i.e. radius] In $ \Delta OAB, $ $ \angle OAB+\angle OBA+\angle AOB=180{}^\circ $

$ \Rightarrow $ $ 50{}^\circ +50{}^\circ +\angle AOB=180{}^\circ $

$ \Rightarrow $ $ \angle AOB=80{}^\circ $

$ \therefore $ $ \angle BOD=(180{}^\circ =80{}^\circ )=100{}^\circ $

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Quantitative Aptitude Ques 1978

Question: In the given figure, O is the centre of a circle and $ \angle OAB=50{}^\circ . $ Then, $ \angle BOD $ is equal to

Options:

Answer:

Solution:

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