A) $ \frac{3}{2} $
B) $ \sqrt{2} $
C) $ \frac{5}{2} $
D) $ \frac{5}{4} $
Correct Answer: D
$ \Rightarrow $ $ (\sec \theta +\tan \theta )(\sec \theta -\tan \theta )=1 $
$ \Rightarrow $ $ \sec \theta -tan\theta =\frac{1}{2} $ (i) and given, $ \sec \theta +\tan \theta =2 $ … (ii) On adding Eqs. (i) and (ii), we get $ 2\sec \theta =\frac{1}{2}+2 $
$ \therefore $ $ \sec \theta =\frac{5}{4} $