Options:
A) 6 : 5
B) 9 : 4
C) 12 : 7
D) 7 : 5
Show Answer
Answer:
Correct Answer: D
Solution:
- 1 kg of each mixture is taken
A = 7: 2 = 14 : 4
Gold $ =\frac{14}{18}; $ Copper $ =\frac{4}{18} $
$ B=7:11 $
Gold $ =\frac{7}{18}; $ Copper $ =\frac{11}{18} $
$ \therefore $ Required ratio $ =( \frac{14}{18}+\frac{7}{18} ):( \frac{4}{18}+\frac{11}{18} ) $
= 21: 15 = 7: 5