Quantitative Aptitude Ques 1946
Question: Two vertices of an equilateral triangle are origin and (4, 0). What is the area of the triangle?
Options:
A) $ 4 $ sq units
B) $ \sqrt{3} $ sq units
C) $ 4\sqrt{3} $ sq units
D) $ 2\sqrt{3} $ sq units
Show Answer
Answer:
Correct Answer: C
Solution:
- Since, triangle is equilateral.
$ \therefore $ $ AB=BC=CA $
$ \Rightarrow $ $ BD=\frac{4}{2}=2 $
In $ \Delta ADC, $ $ AD^{2}=4^{2}-2^{2}=16-4=12 $
$ \Rightarrow $ $ AD=2\sqrt{3} $
$ \therefore $ Area of $ \Delta ABC=\frac{1}{2}\times BC\times AD=\frac{1}{2}\times 4\times 2\sqrt{3} $ $ =4\sqrt{3},squnits $
BETA
