Quantitative Aptitude Ques 1934
Question: If an equilateral $ \Delta ABC $ is inscribed in a circle with centre at O, then $ \angle BOC, $ $ \angle COA $ and $ \angle AOB $ are respectively
Options:
A) $ 50{}^\circ , $ $ 60{}^\circ , $ $ 70{}^\circ $
B) $ 120{}^\circ , $ $ 120{}^\circ , $ $ 120{}^\circ $
C) $ 60{}^\circ , $ $ 60{}^\circ , $ $ 60{}^\circ $
D) $ 80{}^\circ , $ $ 120{}^\circ , $ $ 160{}^\circ $
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Answer:
Correct Answer: B
Solution:
- Since, given ABC is an equilateral triangle. So, angle formed by incentre is also equal.
$ \therefore $ $ \angle BOC, $ $ \angle COA $ and $ \angle AOB $ are equal to $ 120{}^\circ . $