Quantitative Aptitude Ques 1932

Question: If A and B together can finish a piece of work in 20 days, B and C in 10 days and C and A in 12 days, then A, B, C jointly can finish the same work in

Options:

A) $ 4\frac{2}{7}days $

B) $ 30days $

C) $ 8\frac{4}{7}days $

D) $ \frac{7}{60}days $

Show Answer

Answer:

Correct Answer: C

Solution:

  • According to the question, (A + B)’s 1 day’s work $ =\frac{1}{20} $ … (i) (B + C)’s 1 day’s work $ =\frac{1}{10} $ … (ii) (C + A)’s 1 day’s work $ =\frac{1}{12} $ … (iii) On adding Eqs. (i), (ii) and (iii), we get $ A+B+B+C+C+A=\frac{1}{20}+\frac{1}{10}+\frac{1}{12} $

$ \Rightarrow $ $ 2,(A+B+C)’=\frac{3+6+5}{60}=\frac{14}{60}=\frac{7}{30} $

$ \therefore $ (A + B + C)’s 1 day’s work $ =\frac{7}{60} $ Hence, the work will be completed in $ \frac{60}{7}=8\frac{4}{7} $ days.

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