SATHEE: Quantitative Aptitude Ques 1930

Quantitative Aptitude Ques 1930

Question: If $ 2\sin[ \frac{(2x+1)\pi }{2} ]=x^{2}+\frac{1}{x^{2}}, $ then the value of $ ( x-\frac{1}{x} ) $ is

Options:

A) $ -1 $

B) $ 2 $

C) $ 1 $

D) $ 0 $

Show Answer

Answer:

Correct Answer: D

Solution:

$ x^{2}+\frac{1}{x^{2}}=2\sin ( \frac{(2x+1)\pi }{2} ) $

$ \Rightarrow $ $ {{( x-\frac{1}{x} )}^{2}}+2=2\sin ( \frac{(2x+1)\pi }{2} ) $ $ [\because ,a^{2}+b^{2}={{(a-b)}^{2}}+2ab] $

$ \therefore $ $ x-\frac{1}{x}=0 $ [ $ \sin \frac{(2x+1)\pi }{2}=1 $ for all integer values of $ x $ ]

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Quantitative Aptitude Ques 1930

Question: If $ 2\sin[ \frac{(2x+1)\pi }{2} ]=x^{2}+\frac{1}{x^{2}}, $ then the value of $ ( x-\frac{1}{x} ) $ is

Options:

Answer:

Solution:

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