Question: A boy walking at a speed of 15 km/h reaches his school 20 min late. Next time he increases his speed by 5 km/h but still he late by 5 min. Find the distance of the school from his home.
Options:
A) 5 km
B) 10 km
C) 15 km
D) 20 km
Show Answer
Answer:
Correct Answer: C
Solution:
- Let the distance $ =x $
Here, the difference in time $ =20-5=15\min $
$ =\frac{15}{60}=\frac{1}{4}h $
Speed during next journey $ =15+5=20km/h $
According to the question,
$ \frac{x}{5}-\frac{x}{20}=\frac{1}{4} $
$ \Rightarrow $ $ \frac{4x-3x}{60}=\frac{1}{4} $
$ \Rightarrow $ $ x=\frac{60}{4}=15 $