Quantitative Aptitude Ques 1923

Question: A boy walking at a speed of 15 km/h reaches his school 20 min late. Next time he increases his speed by 5 km/h but still he late by 5 min. Find the distance of the school from his home.

Options:

A) 5 km

B) 10 km

C) 15 km

D) 20 km

Show Answer

Answer:

Correct Answer: C

Solution:

  • Let the distance $ =x $ Here, the difference in time $ =20-5=15\min $ $ =\frac{15}{60}=\frac{1}{4}h $ Speed during next journey $ =15+5=20km/h $ According to the question, $ \frac{x}{5}-\frac{x}{20}=\frac{1}{4} $

$ \Rightarrow $ $ \frac{4x-3x}{60}=\frac{1}{4} $
$ \Rightarrow $ $ x=\frac{60}{4}=15 $