Quantitative Aptitude Ques 1917

Question: What was the day of the week on 17th August, 2010?

Options:

A) Sunday

B) Wednesday

C) Tuesday

D) Friday

Show Answer

Answer:

Correct Answer: C

Solution:

  • Period upto 17th August, 2010 = (year 2009 + Period from 1.1,2010 to 17. 8.2010) Odd days in 1600 yr = 0 Odd days in 400 yr = 0 9 yr= (2 leap years + 7 ordinary years) $ =(2\times 2+7\times 1)=1week+4days $ = 4 odd days Number of days between 1.1. 2010 to 17.8.2010 = January + February + March + April + May + June + July + August $ =(31+28+31+30+31+30+31+17)days $ = 229 days = 32 weeks + 5 odd days Total number of odd days $ =(0+0+4+5)days $ = 9 days = 1 week + 2 odd days Hence, the required day is Tuesday.
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