Quantitative Aptitude Ques 1914
Question: Directions: In these questions, two equations numbered I and II are given. You have to solve both the equations and mark the appropriate option, [IBPS (PO/MT) 2015]
I. $ 3x^{2}+11x+6=0 $
II. $ 3y^{2}+10y+8=0 $
Options:
A) If $ x>y $
B) If $ x<y $
C) If $ x\ge y $
D) If $ x\le y $
E) If relationship between x and y cannot be established
Show Answer
Answer:
Correct Answer: E
Solution:
- I. $ 3x^{2}+11x+6=0 $
$ \Rightarrow $ $ 3x^{2}+9x+2x+6=0 $
$ \Rightarrow $ $ 3x(x+3)+2(x+3)=0 $
$ \Rightarrow $ $ (3x+2)(x+3)=0 $
$ \Rightarrow $ $ x=-3, $ $ -2/3 $ II. $ 3y^{2}+10y+8=0 $
$ \Rightarrow $ $ 3y^{2}+6y+4y+8=0 $
$ \Rightarrow $ $ 3y(y+2)+4(y+2)=0 $
$ \Rightarrow $ $ y=-2, $ $ -\frac{4}{3} $
$ \therefore $ Relationship cannot be determined.
BETA
