Quantitative Aptitude Ques 1914

Question: Directions: In these questions, two equations numbered I and II are given. You have to solve both the equations and mark the appropriate option, [IBPS (PO/MT) 2015]

I. $ 3x^{2}+11x+6=0 $
II. $ 3y^{2}+10y+8=0 $

Options:

A) If $ x>y $

B) If $ x<y $

C) If $ x\ge y $

D) If $ x\le y $

E) If relationship between x and y cannot be established

Show Answer

Answer:

Correct Answer: E

Solution:

  • I. $ 3x^{2}+11x+6=0 $

$ \Rightarrow $ $ 3x^{2}+9x+2x+6=0 $

$ \Rightarrow $ $ 3x(x+3)+2(x+3)=0 $

$ \Rightarrow $ $ (3x+2)(x+3)=0 $

$ \Rightarrow $ $ x=-3, $ $ -2/3 $ II. $ 3y^{2}+10y+8=0 $

$ \Rightarrow $ $ 3y^{2}+6y+4y+8=0 $

$ \Rightarrow $ $ 3y(y+2)+4(y+2)=0 $
$ \Rightarrow $ $ y=-2, $ $ -\frac{4}{3} $

$ \therefore $ Relationship cannot be determined.