A) 8 yr
B) 12 yr
C) 16 yr
D) 24 yr
Correct Answer: A
$ \Rightarrow $ $ 2={{( 1+\frac{R}{100} )}^{4}} $
$ \Rightarrow $ $ {2^{\frac{1}{4}}}=( 1+\frac{R}{100} ) $ Let the sum become 4 times in T yr. Then, $ 4P=P{{( 1+\frac{R}{100} )}^{T}} $
$ \Rightarrow $ $ 4={{( 1+\frac{R}{100} )}^{T}} $
$ \Rightarrow $ $ 4={{( {2^{\frac{1}{4}}} )}^{T}} $
$ \Rightarrow $ $ 4={2^{\frac{T}{4}}} $
$ \Rightarrow $ $ 2^{2}={2^{\frac{T}{4}}} $
$ \Rightarrow $ $ T=4\times 2=8yr $