Question: A can solve 40% of the problem given in a book and B can solve 70%. What is the probability that atleast one of them will solve the problem selected at random from the book?
Options:
A) 0.95
B) 0.90
C) 0.89
D) 0.97
Show Answer
Answer:
Correct Answer: D
Solution:
- Let Event X : A solve the problem
Event Y : B solve the problem
Clearly, X and Y are independent events such that
$ P(X)=\frac{90}{100}=\frac{9}{10} $
$ \Rightarrow $ $ P(Y)=\frac{70}{100}=\frac{7}{10} $
$ \therefore $ Required probability,
$ P(X\cup Y)=1-\overline{P(X)},\overline{P(Y)}=1-( 1-\frac{9}{10} )( 1-\frac{7}{10} ) $ $ =1-( \frac{1}{10}\times \frac{3}{10} )=\frac{97}{100}=0.97 $