Quantitative Aptitude Ques 1894

Question: A can solve 40% of the problem given in a book and B can solve 70%. What is the probability that atleast one of them will solve the problem selected at random from the book?

Options:

A) 0.95

B) 0.90

C) 0.89

D) 0.97

Show Answer

Answer:

Correct Answer: D

Solution:

  • Let Event X : A solve the problem Event Y : B solve the problem Clearly, X and Y are independent events such that $ P(X)=\frac{90}{100}=\frac{9}{10} $
    $ \Rightarrow $ $ P(Y)=\frac{70}{100}=\frac{7}{10} $

$ \therefore $ Required probability, $ P(X\cup Y)=1-\overline{P(X)},\overline{P(Y)}=1-( 1-\frac{9}{10} )( 1-\frac{7}{10} ) $ $ =1-( \frac{1}{10}\times \frac{3}{10} )=\frac{97}{100}=0.97 $