Quantitative Aptitude Ques 189
Question: In the given figure, BOC is a diameter of a circle with centre O. If $ \angle BCA=30{}^\circ , $ then $ \angle CDA $ is equal to
Options:
A) $ 30{}^\circ $
B) $ 45{}^\circ $
C) $ 60{}^\circ $
D) $ 50{}^\circ $
Show Answer
Answer:
Correct Answer: C
Solution:
- $ \angle BAC=90{}^\circ $ [angles in a semi-circle] In $ \Delta ABC, $ $ \angle BAC+\angle ABC+\angle BCA=180{}^\circ $
$ \Rightarrow $ $ 90{}^\circ +\angle ABC+30{}^\circ =180{}^\circ $
$ \Rightarrow $ $ \angle ABC=60{}^\circ $
$ \therefore $ $ \angle CDA=\angle ABC=60{}^\circ $ [angles in the same segment of a circle]
BETA
