SATHEE: Quantitative Aptitude Ques 189

Quantitative Aptitude Ques 189

Question: In the given figure, BOC is a diameter of a circle with centre O. If $ \angle BCA=30{}^\circ , $ then $ \angle CDA $ is equal to

Options:

A) $ 30{}^\circ $

B) $ 45{}^\circ $

C) $ 60{}^\circ $

D) $ 50{}^\circ $

Show Answer

Answer:

Correct Answer: C

Solution:

$ \angle BAC=90{}^\circ $ [angles in a semi-circle] In $ \Delta ABC, $ $ \angle BAC+\angle ABC+\angle BCA=180{}^\circ $

$ \Rightarrow $ $ 90{}^\circ +\angle ABC+30{}^\circ =180{}^\circ $

$ \Rightarrow $ $ \angle ABC=60{}^\circ $

$ \therefore $ $ \angle CDA=\angle ABC=60{}^\circ $ [angles in the same segment of a circle]

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Quantitative Aptitude Ques 189

Question: In the given figure, BOC is a diameter of a circle with centre O. If $ \angle BCA=30{}^\circ , $ then $ \angle CDA $ is equal to

Options:

Answer:

Solution:

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