Quantitative Aptitude Ques 1885

Question: In a $ \Delta ABC, $ $ \angle A+\frac{1}{2}\angle B+\angle C=140{}^\circ , $ then $ \angle B $ is

Options:

A) $ 50{}^\circ $

B) $ 80{}^\circ $

C) $ 40{}^\circ $

D) $ 60{}^\circ $

Show Answer

Answer:

Correct Answer: B

Solution:

  • In $ \Delta ABC, $ $ \angle A+\angle B+\angle C=180{}^\circ $ Now, $ \angle A+\frac{\angle B}{2}+\angle C=140{}^\circ $ $ \angle A+\angle B+\angle C=140{}^\circ +\frac{\angle B}{2} $ $ 180{}^\circ -140{}^\circ =\frac{\angle B}{2} $
    $ \Rightarrow $ $ \angle B=80 $
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