SATHEE: Quantitative Aptitude Ques 1877

Quantitative Aptitude Ques 1877

Question: A certain sum is divided among P, Q and R in such a way that P gets Rs. 40 more than the $ \frac{1}{2} $ of the sum. Q gets Rs. 120 less than $ \frac{3}{8}th $ of the sum and R get Rs. 200. What is the total sum? [IBPS (PO/MT) Pre 2015]

Options:

A) Rs. 960

B) Rs. 850

C) Rs. 906

D) Rs. 805

E) None of these

Show Answer

Answer:

Correct Answer: A

Solution:

Let the sum be x. P gets $ =\frac{x}{2}+40 $ Q gets $ =\frac{3}{8}x-120 $ R gets $ =200 $ According to the question, $ \frac{x}{2}+40+\frac{3}{8}x-120+200=x $

$ \Rightarrow $ $ \frac{x}{2}+\frac{3}{8}x-x=-,200+120-40 $

$ \Rightarrow $ $ \frac{4x+3x-8x}{8}=-,240+120 $

$ \Rightarrow $ $ \frac{-x}{8}=-120 $
$ \Rightarrow $ $ \frac{x}{8}=120 $

$ \Rightarrow $ $ x=8\times 120=960 $

Quantitative Aptitude Ques 1876

Quantitative Aptitude Ques 1878

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