SATHEE: Quantitative Aptitude Ques 1855

Quantitative Aptitude Ques 1855

Question: Directions: In each of the following questions two equations are given, solve these equations and give answer. [IBPS (PO) 2013]

I. $ x^{2}+20=9x $
II. $ y^{2}+42=13y $

Options:

A) If $ x\ge y $

B) If $ x>y $

C) If $ x\le y $

D) If $ x<y $

E) If $ x=y $

Show Answer

Answer:

Correct Answer: D

Solution:

I. $ x^{2}+20=9x $

$ \Rightarrow $ $ x^{2}-9x+20=0 $

$ \Rightarrow $ $ x^{2}-5x-4x+20=0 $

$ \Rightarrow $ $ x(x-5)-4(x-5)=0 $

$ \Rightarrow $ $ (x-4)(x-5)=0 $

$ \therefore $ $ x=4, $ $ 5 $ II. $ y^{2}+42=13y $

$ \Rightarrow $ $ y^{2}-13y+42=0 $

$ \Rightarrow $ $ y^{2}-7y-6y+42=0 $

$ \Rightarrow $ $ y(y-7)-6(y-7)=0 $

$ \Rightarrow $ $ (y-6)(y-7)=0 $

$ \therefore $ $ y=6,7 $ Hence, $ x<y $

Quantitative Aptitude Ques 1854

Quantitative Aptitude Ques 1856

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