Quantitative Aptitude Ques 1854

Question: Directions: In each of the following questions two equations are given, solve these equations and give answer. [IBPS (PO) 2013]

I. $ x^{2}+5x+6=0 $
II. $ y^{2}+7y+12=0 $

Options:

A) If $ x\ge y $

B) If $ x>y $

C) If $ x\le y $

D) If $ x<y $

E) If $ x=y $

Show Answer

Answer:

Correct Answer: A

Solution:

  • I. $ x^{2}+5x+6=0 $

$ \Rightarrow $ $ x^{2}+2x+3x+6=0 $

$ \Rightarrow $ $ x(x+2)+3(x+2)=0 $
$ \Rightarrow $ $ (x+3)(x+2)=0 $

$ \therefore $ $ x=-3, $ $ -2 $ II. $ y^{2}+7y+12=0 $

$ \Rightarrow $ $ y^{2}+3y+4y+12=0 $

$ \Rightarrow $ $ y(y+3)+4(y+3)=0 $

$ \Rightarrow $ $ (y+4)(y+3)=0 $

$ \therefore $ $ y=-3, $ $ -4 $ Hence, $ x\ge y $

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