Quantitative Aptitude Ques 1847
Question: The vertices of a triangle are $ A(4,4), $ $ B(3,-2) $ and $ C(-3,16). $ The area of the triangle is
Options:
A) 30 sq units
B) 36 sq units
C) 27 sq units
D) 40 sq units
Show Answer
Answer:
Correct Answer: C
Solution:
- Let $ x _1=4, $ $ x _2=3 $ and $ x _3=-3, $ $ y _1=4, $ $ y _2=-2 $ and $ y _3=16 $
$ \therefore $ Area of triangle $ =| \frac{1}{2}{x _1(y _2-y _3)+x _2(y _3-y _1)+x _3(y _1-y _2)} | $ $ =| \frac{1}{2}{4(-2-16)+3(16-4)+(-3)(4+2)} | $ $ =| \frac{1}{2}(-72+36-18) |=| \frac{1}{2}\times (-54) |=27squnits $
BETA
