Quantitative Aptitude Ques 1847

Question: The vertices of a triangle are $ A(4,4), $ $ B(3,-2) $ and $ C(-3,16). $ The area of the triangle is

Options:

A) 30 sq units

B) 36 sq units

C) 27 sq units

D) 40 sq units

Show Answer

Answer:

Correct Answer: C

Solution:

  • Let $ x _1=4, $ $ x _2=3 $ and $ x _3=-3, $ $ y _1=4, $ $ y _2=-2 $ and $ y _3=16 $

$ \therefore $ Area of triangle $ =| \frac{1}{2}{x _1(y _2-y _3)+x _2(y _3-y _1)+x _3(y _1-y _2)} | $ $ =| \frac{1}{2}{4(-2-16)+3(16-4)+(-3)(4+2)} | $ $ =| \frac{1}{2}(-72+36-18) |=| \frac{1}{2}\times (-54) |=27squnits $

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