SATHEE: Quantitative Aptitude Ques 1840

Quantitative Aptitude Ques 1840

Question: Directions: In each of the following questions two equations are given. Solve these equations and give answer. [IBPS (SO) 2013]

I. $ 10x^{2}-7x+1=0 $
II. $ 35y^{2}-12y+1=0 $

Options:

A) If $ x<y $

B) If $ x>y $

C) If $ x=y $

D) If $ x\ge y $

E) If $ x\le y $

Show Answer

Answer:

Correct Answer: D

Solution:

I. $ 10x^{2}-7x+1=0 $

$ \Rightarrow $ $ 10x^{2}-5x-2x+1=0 $

$ \Rightarrow $ $ 5x(2x-1)-1(2x-1)=0 $

$ \Rightarrow $ $ (5x-1)(2x-1)=0 $

$ \therefore $ $ x=\frac{1}{5}, $ $ \frac{1}{2} $ II. $ 35y^{2}-12y+1=0 $

$ \Rightarrow $ $ 35y^{2}-7y-5y+1=0 $

$ \Rightarrow $ $ 7y(5y-1)-1(5y-1)=0 $

$ \Rightarrow $ $ (5y-1)(7y-1)=0 $

$ \therefore $ $ y=\frac{1}{5}, $ $ \frac{1}{7} $ Hence, $ x\ge y $

Quantitative Aptitude Ques 1839

Quantitative Aptitude Ques 1841

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