Quantitative Aptitude Ques 1839
Question: Directions: In each of the following questions two equations are given. Solve these equations and give answer. [IBPS (SO) 2013]
I. $ x^{2}-6x=7 $
II. $ 2y^{2}+13y+15=0 $
Options:
A) If $ x<y $
B) If $ x>y $
C) If $ x=y $
D) If $ x\ge y $
E) If $ x\le y $
Show Answer
Answer:
Correct Answer: B
Solution:
- I. $ x^{2}-6x-7=0 $
$ \Rightarrow $ $ x^{2}-7x+x-7=0 $
$ \Rightarrow $ $ x(x-7)+1(x-7)=0 $
$ \therefore $ $ x=-1, $ $ 7 $ II. $ 2y^{2}+13y+15=0 $
$ \Rightarrow $ $ 2y^{2}+10y+3y+15=0 $
$ \Rightarrow $ $ 2y(y+5)+3(y+5)=0 $
$ \Rightarrow $ $ (2y+3)(y+5)=0 $
$ \therefore $ $ y=-\frac{3}{2}, $ $ -5 $ Hence, $ x>y $
BETA
