Question: A, B and C can do a piece of work in 24, 30 and 40 days, respectively. They began the work together but C left 4 days before completion of the work. In how many days was the work done?
Options:
A) 11
B) 12
C) 18
D) 14
Show Answer
Answer:
Correct Answer: A
Solution:
- Work done by A in one day $ =\frac{1}{24} $
Word done by B in one day $ =\frac{1}{30} $
Work done by C in one day $ =\frac{1}{40} $
Work done by (A + B + C) in 1 day
$ =\frac{1}{24}+\frac{1}{30}+\frac{1}{40}=\frac{5+4+3}{120}=\frac{12}{120} $
Work done by (A + B) in 1 day
$ =\frac{1}{24}+\frac{1}{30}=\frac{5+4}{120}=\frac{9}{120} $
Work done by (A + B) in last 4 days $ =\frac{9}{120}\times 4=\frac{36}{120} $
$ \therefore $ Work done by (A + B + C) $ =1-\frac{36}{120}=\frac{84}{120} $
Time taken by (A + B + C) to complete the $ \frac{84}{120} $ work
$ =\frac{84}{120}\times \frac{120}{12}=7days $
$ \therefore $ Total time taken to complete the work
$ =7+4=11days $