Question: Pipe A can fill a tank in 30 min, while pipe B cam fill the same tank in 10 min and pipe C can empty the full tank in 40 min. If all the pipes are opened together, then how much time will be needed to make the tank full?
Options:
A) $ 9\frac{3}{13}h $
B) $ 9\frac{4}{13}h $
C) $ 9\frac{7}{13}h $
D) $ 9\frac{9}{13}h $
E) None of these
Show Answer
Answer:
Correct Answer: A
Solution:
- Part filled by A in 1 min $ =\frac{1}{30} $
Part filled by B in 1 min $ =\frac{1}{10} $
Part emptied by the C in 1 min $ =-\frac{1}{40} $
Net part filled in 1 h by (A + B + C)
$ =( \frac{1}{30}+\frac{1}{10}-\frac{1}{40} )=\frac{4+12-3}{120}=\frac{13}{120} $
$ \therefore $ Required time to fill the tank $ =\frac{120}{13}=9\frac{3}{13}h $