Question: A 125 m long train take 25 s to cross a person who is going in the same direction with the speed of 4 km/h. After crossing that person, the train can reach next station in 30 min. How long that person takes to reach that station after being crossed by them?
Options:
A) $ 3\frac{1}{4}h $
B) $ 2\frac{3}{4}h $
C) $ 3\frac{3}{4}h $
D) $ 2\frac{1}{4}h $
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Answer:
Correct Answer: B
Solution:
- Speed of the person $ =4km/h $
$ =4\times \frac{5}{18}m/s=\frac{10}{9}m/s $
Let speed of train be $ xm/s. $
Then, relative speed of train $ =( x-\frac{10}{9} )m/s $
As, train takes 25 s to cross the person.
$ \therefore $ $ 25=\frac{125}{( x-\frac{10}{9} )} $
$ \Rightarrow $ $ x-\frac{10}{9}=5 $
$ \Rightarrow $ $ x=\frac{55}{9}m/s $
Now, distance covered by the train in 30 min
$ =\frac{55}{9}\times 30\times 60 $
$ =11000m=11km $
Thus, time taken by the person to cover the distance of
$ 11km=\frac{11}{4}h=2\frac{3}{4}h $