Quantitative Aptitude Ques 1819
Question: What was the day of the week on 5th June, 2002?
Options:
A) Wednesday
B) Saturday
C) Friday
D) Monday
E) None of these
Show Answer
Answer:
Correct Answer: A
Solution:
- Period upto 5th June, 2002 = (Year 2001 + Period from 1.1.2002 to 5.6.2002)
$ \therefore $ Odd days in 1600 yr = 0 Odd days in 400 yr = 0 Odd days in 1 ordinary year = 1 Odd days in year 2001 $ =(0+0+1)=1 $ Number of days from 1.1.2002 to 5.6,2002 January + February + March + April + May + June $ =31+28+31+30+31+5 $ = 156 days = 22 weeks + 2 days = 2 odd days
$ \therefore $ Total number of odd days $ =(1+2)=3 $ Hence, the required day is Wednesday.
BETA
