Question: The arithmetic mean of the scores of a group of students in a test was 52. The brightest 20% of them secured a mean score of 80 and the dullest 25% a mean source of 31. The mean score of remaining 55% is
Options:
A) 45%
B) 50%
C) 51.4% (approx)
D) 54.6% (approx)
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Answer:
Correct Answer: C
Solution:
- Let mean score of remaining 55% = x
$ 52=\frac{20\times 80+25\times 31+55\times x}{100} $
$ \Rightarrow $ $ 5200=1600+775+55x $
$ \Rightarrow $ $ 55x=5200-1600-775=2825 $
$ \therefore $ $ x=\frac{2825}{25}=51.36,\text{(approx)} $