Quantitative Aptitude Ques 1787
Question: $ {{(0.49)}^{4}}\times {{(0.343)}^{4}}\div {{(0.2401)}^{4}}={{(70\div 100)}^{?+3}} $ [IBPS (SO) 2012]
Options:
A) 3
B) 1
C) 4
D) 7
E) None of these
Show Answer
Answer:
Correct Answer: B
Solution:
- $ {{(70\div 100)}^{?+3}}={{(0.49)}^{4}}\times {{(0.343)}^{4}}\div {{(0.2401)}^{4}} $
$ \Rightarrow $ $ {{(0.7)}^{?+3}}={{( \frac{0.49\times 0.343}{0.2401} )}^{4}} $
$ \Rightarrow $ $ {{(0.7)}^{?+3}}={{(0.7)}^{4}} $ On comparing the exponents both sides, we get $ ?,+3=4 $
$ \therefore $ $ ?=4-3=1 $
BETA
