Quantitative Aptitude Ques 1787

Question: $ {{(0.49)}^{4}}\times {{(0.343)}^{4}}\div {{(0.2401)}^{4}}={{(70\div 100)}^{?+3}} $ [IBPS (SO) 2012]

Options:

A) 3

B) 1

C) 4

D) 7

E) None of these

Show Answer

Answer:

Correct Answer: B

Solution:

  • $ {{(70\div 100)}^{?+3}}={{(0.49)}^{4}}\times {{(0.343)}^{4}}\div {{(0.2401)}^{4}} $

$ \Rightarrow $ $ {{(0.7)}^{?+3}}={{( \frac{0.49\times 0.343}{0.2401} )}^{4}} $

$ \Rightarrow $ $ {{(0.7)}^{?+3}}={{(0.7)}^{4}} $ On comparing the exponents both sides, we get $ ?,+3=4 $

$ \therefore $ $ ?=4-3=1 $

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