A) 4th, 5th, 9th, 12th
B) 5th, 12th, 19th, 26th
C) 3rd, 10th, 17th, 25th
D) 4th, 11th, 18th, 25th
E) None of the above
Correct Answer: B
$ \therefore $ Odd day in 1600 yr = 0 Odd day in 400 yr = 0 4 yr = (1 leap year + 3 ordinary years) $ =(1\times 2+3\times 1)=5 $ odd days Number of days between 1.1.2005 to 1.3.2005. January + February + March = 31 + 28 + 1 = 60 days = (8 weeks + 4 days = 4 odd days Total number of odd days $ =(0+0+5+4)=9 $ = 1 week + 2 days = 2 odd days
$ \therefore $ 1.3.2005 was Tuesday. So, Saturday will fall on 5.3.2005. Hence, Saturday lies on 5th, 12th, 19th and 26th of March 2005.