Quantitative Aptitude Ques 176

Question: If the radii of the circular ends of a truncated conical bucket which is 45 cm high is 28 cm and 7 cm, then the capacity of the bucket in cubic centimetres is $ ( take,\pi =\frac{22}{7} ) $

Options:

A) 48510

B) 45810

C) 48150

D) 48051

Show Answer

Answer:

Correct Answer: A

Solution:

  • Volume of bucket $ =\frac{1}{3}\pi h(r^{2}+R^{2}+rR) $ $ =\frac{1}{3}\times \frac{22}{7}\times 45,[28^{2}+7^{2}+(28\times 7)] $ $ =\frac{1}{3}\times \frac{22}{7}\times 45,(784+49+196) $ $ =\frac{1}{3}\times \frac{22}{7}\times 45\times 1029=48510,cm^{3} $