Quantitative Aptitude Ques 176
Question: If the radii of the circular ends of a truncated conical bucket which is 45 cm high is 28 cm and 7 cm, then the capacity of the bucket in cubic centimetres is $ ( take,\pi =\frac{22}{7} ) $
Options:
A) 48510
B) 45810
C) 48150
D) 48051
Show Answer
Answer:
Correct Answer: A
Solution:
- Volume of bucket $ =\frac{1}{3}\pi h(r^{2}+R^{2}+rR) $
$ =\frac{1}{3}\times \frac{22}{7}\times 45,[28^{2}+7^{2}+(28\times 7)] $
$ =\frac{1}{3}\times \frac{22}{7}\times 45,(784+49+196) $
$ =\frac{1}{3}\times \frac{22}{7}\times 45\times 1029=48510,cm^{3} $