Quantitative Aptitude Ques 1747

Question: Which term of the series $ 8+1.6+32+… $ is $ 0.00256 $ ?

Options:

A) 5

B) 7

C) 9

D) 6

Show Answer

Answer:

Correct Answer: D

Solution:

  • $ a=8 $
    $ \Rightarrow $ $ r=\frac{1.6}{8}=\frac{1}{5} $ Let 0.00256 be the nth term.

$ \therefore $ $ T _{n}=a{r^{(n-1)}} $

$ \Rightarrow $ $ 0.00256=8\times {{( \frac{1}{5} )}^{n-1}} $

$ \Rightarrow $ $ {{( \frac{1}{5} )}^{n-1}}=0.00032 $

$ \Rightarrow $ $ {{( \frac{1}{5} )}^{n-1}}=\frac{32}{100000} $
$ \Rightarrow $ $ {{( \frac{1}{5} )}^{n-1}}={{( \frac{1}{5} )}^{5}} $

$ \therefore $ $ n-1=5 $
$ \Rightarrow $ $ n=6 $