Quantitative Aptitude Ques 1722
Question: Directions: In each of these questions two equations I and II are given. You have to solve both the equations and give answer. [IBPS (SO) 2014]
I. $ 6x^{2}-7x+2=0 $
II. $ 20y^{2}-31y+12=0 $
Options:
A) If $ x\ge y $
B) If $ x>y $
C) If $ x\le y $
D) If $ x<y $
E) If relationship between x and y cannot be established
Show Answer
Answer:
Correct Answer: D
Solution:
- I. $ 6x^{2}-7x+2=0 $
$ \Rightarrow $ $ 6x^{2}-4x-3x+2=0 $
$ \Rightarrow $ $ 2x(3x-2)-1(3x-2)=0 $
$ \Rightarrow $ $ (2x-1)(3x-2)=0 $
$ \Rightarrow $ $ x=\frac{1}{2}, $ $ \frac{2}{3} $
II. $ 20y^{2}-31y+12=0 $
$ \Rightarrow $ $ 20y^{2}-15y-16y+12=0 $
$ \Rightarrow $ $ 5y(4y-3)-4(4y-3)=0 $
$ \Rightarrow $ $ (5y-4)(4y-3)=0 $
$ \therefore $ $ y=\frac{4}{3}, $ $ \frac{3}{4} $ Hence, $ y>x $
BETA
