SATHEE: Quantitative Aptitude Ques 1720

Quantitative Aptitude Ques 1720

Question: Directions: In each of these questions two equations I and II are given. You have to solve both the equations and give answer. [IBPS (SO) 2014]

I. $ 2x^{2}+5x+3=0 $
II. $ y^{2}+9y+14=0 $

Options:

A) If $ x\ge y $

B) If $ x>y $

C) If $ x\le y $

D) If $ x<y $

E) If relationship between x and y cannot be established

Show Answer

Answer:

Correct Answer: B

Solution:

I. $ 2x^{2}+5x+3=0 $

$ \Rightarrow $ $ 2x^{2}+2x+3x+3=0 $

$ \Rightarrow $ $ 2x(x+1)+3(x+1)=0 $

$ \Rightarrow $ $ (x+1)(2x+3)=0 $

$ \therefore $ $ x=-\frac{3}{2}, $ $ -1 $ II. $ y^{2}+9y+14=0 $

$ \Rightarrow $ $ y^{2}+7y+2y+14=0 $

$ \Rightarrow $ $ y(y+7)+2(y+7)=0 $

$ \Rightarrow $ $ (y+2)(y+7)=0 $

$ \therefore $ $ y=-2, $ $ -7 $ Hence, $ x>y $

Quantitative Aptitude Ques 1719

Quantitative Aptitude Ques 1721

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