SATHEE: Quantitative Aptitude Ques 1704

Quantitative Aptitude Ques 1704

Question: A can do a piece of work in 15 days. With the help of A, B can do it in $ 6\frac{2}{3} $ days. B can do it alone in

Options:

A) 13 days

B) 8 days

C) 10 days

D) 12 days

Show Answer

Answer:

Correct Answer: D

Solution:

Total work done by A in 15 days.

$ \therefore $ A’s one day work $ =\frac{1}{15} $ A and B can do working together in $ 6\frac{2}{3} $ days $ =\frac{20}{3} $ days.

$ \therefore $ One day work of A and $ B=\frac{3}{20}. $ Let work done B alone be x days.

$ \therefore $ One day work of $ B=1/x $

$ \therefore $ $ \frac{1}{x}+\frac{1}{15}=\frac{3}{20} $
$ \Rightarrow $ $ \frac{1}{x}=\frac{3}{20}-\frac{1}{15} $

$ \Rightarrow $ $ \frac{1}{x}=\frac{9-4}{60} $
$ \Rightarrow $ $ \frac{1}{x}=\frac{5}{60} $

$ \Rightarrow $ $ \frac{1}{x}=\frac{1}{12} $

$ \therefore $ One day work of $ B=1/12 $ Hence, B alone can do complete work in 12 days.

Quantitative Aptitude Ques 1703

Quantitative Aptitude Ques 1705

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