SATHEE: Quantitative Aptitude Ques 1703

Quantitative Aptitude Ques 1703

Question: The price of sugar having gone down by 10%, a consumer can buy 5 kg more sugar for Rs. 270. The difference between the original and reduced price per kg is

Options:

A) 62 paise

B) 60 paise

C) 75 paise

D) 53 paise

Show Answer

Answer:

Correct Answer: B

Solution:

Let the original price of sugar be Rs. x. Then, reduced price of sugar $ =x-\frac{10x}{100}=\frac{90x}{100}=Rs\text{. }\frac{9x}{10} $ Now, according to the question, $ \frac{270}{9x/10}-\frac{270}{x}=5 $

$ \Rightarrow $ $ \frac{270/10}{9x}-\frac{270}{x}=5 $

$ \Rightarrow $ $ \frac{300}{x}-\frac{270}{x}=5 $
$ \Rightarrow $ $ \frac{300-270}{x}=5 $

$ \therefore $ $ x=\frac{30}{5}=6 $

$ \therefore $ Original price of sugar = Rs. 6 Reduced price of sugar $ =\frac{9\times x}{10}=\frac{9\times 6}{10}=Rs\text{. 5}\text{.40} $

$ \therefore $ Required difference $ =(6-5.40)=Rs\text{. 0}\text{.60} $ or 60 paise

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