A) $ 9\frac{1}{11} $ %
B) 10%
C) $ 9\frac{1}{8} $ %
D) $ 9\frac{1}{7} $ %
Correct Answer: A
$ \therefore $ Area of triangle $ =\frac{1}{2}\times b\times h $ $ =\frac{1}{2}\times 10\times 10=50,cm^{2} $ If height is increased by 10%, then new height = 11cm and $ \frac{1}{2}\times b\times 11=50 $
$ \Rightarrow $ $ b=\frac{100}{11}cm $
$ \therefore $ Reduction in base $ =\frac{(10-\frac{100}{11})}{10}\times 100=\frac{10}{\frac{11}{10}}\times 100 $ $ =\frac{1}{11}\times 100=9\frac{1}{11} $ %