Quantitative Aptitude Ques 1699

Question: A bag contains 4 white and 6 red balls. Two draws of one ball each are made without replacement. The probability that one is red and other white, is

Options:

A) $ \frac{10}{15} $

B) $ \frac{6}{9} $

C) $ \frac{8}{15} $

D) $ \frac{4}{9} $

Show Answer

Answer:

Correct Answer: C

Solution:

  • $ W _1= $ Drawing white ball for first time $ P(W _1)4/10 $ $ W _2= $ Drawing white ball in second time $ P(W _2/R _1)=4/9 $ $ R _1= $ Drawing red ball for first time $ P(R _1)=6/10 $ $ R _2= $ Drawing red ball for second time $ P(R _2/W _1)=6/9 $ P (one red and three white) $ =P(R _1)-P(W _2/R _1)+P(W _1)-P(R _2/W _1) $ $ =\frac{6}{10}\times \frac{4}{9}+\frac{4}{10}\times \frac{6}{9}=\frac{48}{90}=\frac{8}{15} $
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