Question: The greatest number of six digits exactly divisible by 24, 15 and 36, is
Options:
A) 999720
B) 999629
C) 999320
D) 999620
Show Answer
Answer:
Correct Answer: A
Solution:
- $ \therefore $ LCM of $ 24, $ $ 15, $ $ 36 $ $ =3\times 2\times 2\times 2\times 5\times 3=360 $
Greatest number of 6 digits $ =999999 $
When 999999 is divided by 360, we get 279 as remainder.
$ \therefore $ Required number $ =999999-279=999720 $