A) $ N^{2}-2 $
B) $ 2,N^{2}-2 $
C) $ 4,N^{2}-2 $
D) $ N^{2} $
Correct Answer: B
$ \Rightarrow $ $ x^{2}+\frac{1}{x^{2}}+2=4N^{2} $ [squaring both sides]
$ \Rightarrow $ $ x^{2}+\frac{1}{x^{2}}=4N^{2}-2=2,(2N^{2}-1) $
$ \Rightarrow $ $ \frac{1}{2}( x^{2}+\frac{1}{x^{2}} )=(2N^{2}-1) $ [divide both sides by 2] Hence, mean of $ x^{2} $ and $ \frac{1}{x^{2}} $ is $ (2N^{2}-1). $