Question: What is the value of $ (90{}^\circ -\theta )\cdot \sin \theta \sec 45{}^\circ ? $
Options:
A) $ 1 $
B) $ \frac{\sqrt{3}}{2} $
C) $ \sqrt{2} $
D) $ \sqrt{3} $
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Answer:
Correct Answer: C
Solution:
- Given, $ \sec (90-\theta ){}^\circ sin\theta sec45{}^\circ $
$ =cosec\theta \sin \theta \sec 45{}^\circ $
$ =\frac{1}{\sin \theta }\cdot \sin \cdot (\sqrt{2})=\sqrt{2} $